Asked by Ava
The coefficient of static friction between a heavy box and a ramp is 0.450, The weight of the box is 1200.0 N and the ramp has an incline of 16.0°. What minimum force is needed for the box to overcome the force of static friction?
a) 1.90 x 102 N
b) 3.80 x 102 N
c) 5.20 x 102 N
d) 7.40 x 102 N
a) 1.90 x 102 N
b) 3.80 x 102 N
c) 5.20 x 102 N
d) 7.40 x 102 N
Answers
Answered by
Anonymous
net force = m a and a = 0 if no motion
our F down ramp = F
total force down = friction force up
F + m g sin 16 = 0.45 * m g cos 16
F = 0.45 * 1200 * 0.961 - 1200 * 0.276
our F down ramp = F
total force down = friction force up
F + m g sin 16 = 0.45 * m g cos 16
F = 0.45 * 1200 * 0.961 - 1200 * 0.276
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