Asked by Dee
The coefficient of static friction between the 3.00 kg crate and the 35.0 degree incline is .300. What minimum force must be applied to the crate from sliding down the incline?
Answers
Answered by
bobpursley
force gravity down plane: 3g*sin35
force friction up plane=mu*3g*cos35
forces up plane=forces down plane
so F+mu*3g*cos35=3g*sin35
so figure and solve for F
force friction up plane=mu*3g*cos35
forces up plane=forces down plane
so F+mu*3g*cos35=3g*sin35
so figure and solve for F
Answered by
Dee
Ok I tried an didn't even come close to the right answer.
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