Asked by Vivian
A right pyramid on a base 4cm square has a slant edge of 6cm.calculate the volume of the pyramid
Answers
Answered by
Reiny
We need the perpendicular height of the pyramid.
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2
then h^2 + (2√2)^2 = 6^2
h^2 = 36 - 8 = 28
h = √28
Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2
then h^2 + (2√2)^2 = 6^2
h^2 = 36 - 8 = 28
h = √28
Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22
Answered by
Anonymous
First find the diagonal of the square, by using Pythagoras theorem, then divide the length of the diagonal by two cos the height of the pyramid now rest on the diagonal and it divided it into two equal parts. Now using half of the diagonal as abase and the slant edge find the height of the pyramid, when u get the height, then use the formula for volume of a pyramid and then find the volume
Answered by
Francis
Very correct and we'll explained.
Good work
Good work
Answered by
Charles
Good
Answered by
Esther
How did you get 28
Answered by
Victor
Good job
And thanks
And thanks
Answered by
Anonymous
I don't understand explain better
Answered by
Stephen
1 1
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