Question
A right pyramid on a base 4cm square has a slant edge of 6cm.calculate the volume of the pyramid
Answers
Reiny
We need the perpendicular height of the pyramid.
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2
then h^2 + (2√2)^2 = 6^2
h^2 = 36 - 8 = 28
h = √28
Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2
then h^2 + (2√2)^2 = 6^2
h^2 = 36 - 8 = 28
h = √28
Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22
Anonymous
First find the diagonal of the square, by using Pythagoras theorem, then divide the length of the diagonal by two cos the height of the pyramid now rest on the diagonal and it divided it into two equal parts. Now using half of the diagonal as abase and the slant edge find the height of the pyramid, when u get the height, then use the formula for volume of a pyramid and then find the volume
Francis
Very correct and we'll explained.
Good work
Good work
Charles
Good
Esther
How did you get 28
Victor
Good job
And thanks
And thanks
Anonymous
I don't understand explain better
Stephen
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