Asked by Kd
The base of a right pyramid is a rectangle of length 80 cm and width 60 cm. Each slant edge of the pyramid is 230 cm. Calculate the volume of the pyramid.
Answers
Answered by
Reiny
Attempt to make a 3-D sketch.
The centre of the pyramid will be the intersection of the two diagonals of the base
and they bisect each other.
let d be that diagonal
d^2 = 80^2 +60^2
d = 100
Now draw a right-angled triangle with base 50 , height = h, and hypotenuse = 230
h^2 + 50^2 = 230^2
find h
volume of pyramid = (1/3)(area of base * h)
The centre of the pyramid will be the intersection of the two diagonals of the base
and they bisect each other.
let d be that diagonal
d^2 = 80^2 +60^2
d = 100
Now draw a right-angled triangle with base 50 , height = h, and hypotenuse = 230
h^2 + 50^2 = 230^2
find h
volume of pyramid = (1/3)(area of base * h)
Answered by
Kd
How did you got base 50 and hy :230
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