Asked by krista
Brookney kicks a soccerball with a speed of 17m/s at 43 degress above the horizon. How far does the ball go before it hits the ground?
Answers
Answered by
Henry
Vo = 17m/s@43deg.
Xo = hor. = 17cos43 = 12.43m/s.
Yo = ver. = 17sin43 = 11.59m/s.
Yf^2 = Yo^2 + 2g*h,
h = (Yf^2 - Yo^2) / 2g,
h = (0 - (11.59)^2) / -19.6 = 6.85m.
D = hor = Vo^2*sin(2A) / g,
D = hor = (17)^2*sin86 / 9.8 = 29.4m.
Xo = hor. = 17cos43 = 12.43m/s.
Yo = ver. = 17sin43 = 11.59m/s.
Yf^2 = Yo^2 + 2g*h,
h = (Yf^2 - Yo^2) / 2g,
h = (0 - (11.59)^2) / -19.6 = 6.85m.
D = hor = Vo^2*sin(2A) / g,
D = hor = (17)^2*sin86 / 9.8 = 29.4m.
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