Asked by Danielle
Seven standard, six-sided dice are rolled, one after the other. What is the probability that:
a) exactly one of them shows a six?
c) there is at least one that shows a six?
a) exactly one of them shows a six?
c) there is at least one that shows a six?
Answers
Answered by
Reiny
prob(6) = 1/6
prob(not6) = 5/6
a) exactly 1 out of 7 tries to be 6
= C(7,1) * (1/6)^1 * (5/6)^6
= .3907 rounded to 4 decimals
b) at least one 6 ---> 1 - prob(all not6)
= 1 - C(7,7) * (1/6)^0 * (5/6)^7
= 1 - .2791
= .7209
prob(not6) = 5/6
a) exactly 1 out of 7 tries to be 6
= C(7,1) * (1/6)^1 * (5/6)^6
= .3907 rounded to 4 decimals
b) at least one 6 ---> 1 - prob(all not6)
= 1 - C(7,7) * (1/6)^0 * (5/6)^7
= 1 - .2791
= .7209
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.