Asked by Hina
how do you solve 2x^2+x^3=96?
Answers
Answered by
Reiny
x^3 + 2x^2 - 96 = 0
tried x = 1,2,3,4 and x=4 worked
by synthetic division
x^3 + 2x^2 - 96 = 0
(x-4)(x^2 + 6x + 24) = 0
solving x^2 + 6x <b>+ 9</b> = -24 + <b>9</b>
(x+3)^2 = -15
x = +3 ± √15 i
x = 4 , 3 ± √15 i
tried x = 1,2,3,4 and x=4 worked
by synthetic division
x^3 + 2x^2 - 96 = 0
(x-4)(x^2 + 6x + 24) = 0
solving x^2 + 6x <b>+ 9</b> = -24 + <b>9</b>
(x+3)^2 = -15
x = +3 ± √15 i
x = 4 , 3 ± √15 i
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