Asked by Hannah

For a chemistry lab the experiment was to carry out an acid-base titration to determine the exact concentration of a sodium hydroxide solution.

Two trials were completed and the data collected was: mass of weighing paper, mass of weighing paper + KHP, mass of KHP, initial buret reading, final buret reading, and volume of NaOH.

The molecular weight of KHP is 204.44 grams/mol.

I need to find the number of moles of KHP, the number of moles of NaOH and the concentration of NaOH but i am not sure how to do this. Please help,thank you!!
Answered by DrBob222
moles KHP = grams/molar mass
moles NaOH = moles KHP
M NaOH = moles NaOH/L NaOH
Answered by Hannah
For my first trial KHP was 1.00g and for the second trial it was the same. So to find moles of KHP would I do 204.44g/mol X 1/1g which would be 204.44g/mol?
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