KHP + NaOH => KNaP + H2O
You took 20 mL of 0.2 M KHP and titrated that with 0.2 M NaOH. I don't have a clue as to the meaning of "equivalence volume of 18 M". Since both KHP and NaOH have the same molarity while KHP and NaOH contain one H and one OH, then the volume at the equivalence point should be 20 mL. (Perhaps you meant 18 mL and you just made a typo and omitted the L of mL).
Ok.I have a titration experiment yesterday 0.2 M of KHP were used and the volume of the titrated solution is 20Ml,it was titrated with 0.2M of NaOH solution with an equivalence volume of 18M.What is the theoretical Equivalence volume of KHP titrated
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