Mavis

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Ok.I have a titration experiment yesterday 0.2 M of KHP were used and the volume of the titrated solution is 20Ml,it was titrated with 0.2M of NaOH solution with an equivalence volume of 18M.What is the theoretical Equivalence volume of KHP titrated

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Then it would be like this -196-{(1.91×10^-1)(298)=5.6918×10^1 } -196+5.6918×10^1=-139.082 Calculation of K -139.082/(8.314×10^-3)×(298) -139.082/2.477572=-56.13641097 E^56.13641097=2.39×10^24

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