A car travleing at 30.6 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s^2. If the coefficient of friction between the road and tires on a rainy day is .083, what is the minimum distance the car will stop?

Answer 1

Work done against friction = Initial K.E.

Ff*X = (M/2)Vo^2 = M*g*0.083 *X

The M's cancel.
Solve for X