Asked by Joshua
A particle of mass 5 kg is acted upon by a horizontal force of magnitude 16 N for 8 seconds, in which time it moves from rest until it is traveling with a speed v m/s. The particle continues to move with this speed for the next 15 seconds. it is brought to rest by the application of a constant resisting force of magnitude Y newtons. The total distance travelled is 1000 m.
2.Find v.
3. what is the total distance travelled while accelerating and traveling at a constant speed?
4. what is the rate at which the speed if the particle decreases before it comes to rest?
5.Find Y.
2.Find v.
3. what is the total distance travelled while accelerating and traveling at a constant speed?
4. what is the rate at which the speed if the particle decreases before it comes to rest?
5.Find Y.
Answers
Answered by
Steve
Start out with F = ma
16 = 5a
a = 3.2
After 8 seconds, v = 3.2x8
When the mass slows down at the end, the force Y is such that
3.2x8 = at
a = 3.2x8/t
Y = 5a
The motion of the mass is thus
s = 1/2 x 3.2 x 8<sup>2</sup> + 3.2x8x15 - 3.2x8t/2 = 1000
Find t, the rest fall out.
16 = 5a
a = 3.2
After 8 seconds, v = 3.2x8
When the mass slows down at the end, the force Y is such that
3.2x8 = at
a = 3.2x8/t
Y = 5a
The motion of the mass is thus
s = 1/2 x 3.2 x 8<sup>2</sup> + 3.2x8x15 - 3.2x8t/2 = 1000
Find t, the rest fall out.