Asked by Cassie
Two Diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10m apart?
Please help, I am very confused with this question, I have completed all other but I am unsure about how to answer this. Any help is greatly appreciated!
Please help, I am very confused with this question, I have completed all other but I am unsure about how to answer this. Any help is greatly appreciated!
Answers
Answered by
Henry
d1 = Vo*t + (g/2)t^2. Vo = 0.
d1 = (g/2)t^2.
d2 = (g/2)(t-1)^2.
d1 = d2 + 10.
(g/2)t^2 = (g/2)(t-1)^2 + 10,
4.9t^2 = 4.9(t-1)^2 + 10,
4.9t^2 - 4.9(t-1)^2 = 10,
divide both sides by 4.9:
t^2 - (t-1)^2 = 2.04,
t^2 - (t^2-2t+1) = 2.04,
t^2 - t^2 + 2t - 1 = 2.04,
2t - 1 = 2.04,
2t = 3.04,
t = 1.52s.
d1 = (g/2)t^2.
d2 = (g/2)(t-1)^2.
d1 = d2 + 10.
(g/2)t^2 = (g/2)(t-1)^2 + 10,
4.9t^2 = 4.9(t-1)^2 + 10,
4.9t^2 - 4.9(t-1)^2 = 10,
divide both sides by 4.9:
t^2 - (t-1)^2 = 2.04,
t^2 - (t^2-2t+1) = 2.04,
t^2 - t^2 + 2t - 1 = 2.04,
2t - 1 = 2.04,
2t = 3.04,
t = 1.52s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.