Question
Two bodies begin to fall freely from the same height but 2nd one falls T seconds ater 1st.The time(after which the 1st body begin to fall) when the diatance between them is L is:
Options
1.T/2 2.T/2+L/gT 3.L/gT 4.T+2L/gT
I am not understanding how to find the time and what is the significance of L how to use ut!??
Options
1.T/2 2.T/2+L/gT 3.L/gT 4.T+2L/gT
I am not understanding how to find the time and what is the significance of L how to use ut!??
Answers
bobpursley
The problem is really worded poorly. It is asking if two objects are dropped at slightly different times, how does the length between them vary with time.
distancefirst=1/2 g t^2
distancesecond=1/2 g(t-T)^2
distance L= distancefirst-distancesecond
= 1/2 g (t^2-(t-T)^2)=L
so solve for t.
1/2 g (t^2-t^2+2tT-T^2)=L
1/2 g T(2t-T)=L
well, you can solve for time t.
distancefirst=1/2 g t^2
distancesecond=1/2 g(t-T)^2
distance L= distancefirst-distancesecond
= 1/2 g (t^2-(t-T)^2)=L
so solve for t.
1/2 g (t^2-t^2+2tT-T^2)=L
1/2 g T(2t-T)=L
well, you can solve for time t.