Asked by shannon
The principal component of many kidney stones is calcium oxalate,CaC2O4. A kidney stone recovered from a typical patient contains 8.50×10^20 formula units of calcium oxalate.
How many moles of CaC2O4 are present in this kidney stone?
How many moles of CaC2O4 are present in this kidney stone?
Answers
Answered by
Steve
1 mole = 6.02x10<sup>23</sup>
so, how many moles in the kidney stone?
8.5x10<sup>20</sup>/6.02x10<sup>23</sup>
= 1.41x10<sup>-3</sup> = 0.00141
so, how many moles in the kidney stone?
8.5x10<sup>20</sup>/6.02x10<sup>23</sup>
= 1.41x10<sup>-3</sup> = 0.00141
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.