Question

The principal component of many kidney stones is calcium oxalate,CaC2O4. A kidney stone recovered from a typical patient contains 8.50×10^20 formula units of calcium oxalate.

How many moles of CaC2O4 are present in this kidney stone?

Answers

1 mole = 6.02x10<sup>23</sup>

so, how many moles in the kidney stone?

8.5x10<sup>20</sup>/6.02x10<sup>23</sup>
= 1.41x10<sup>-3</sup> = 0.00141

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