Asked by Sydney
                The x component of a certain vector is -86.0 units and the y component is +75.0 units.
The magnitude of the vector is 114 m.
What is the angle between the direction of the vector and the positive direction of x? Use the convention that positive angles are measured counterclockwise from the +x axis and negative angles are measured clockwise from the +x axis.
            
        The magnitude of the vector is 114 m.
What is the angle between the direction of the vector and the positive direction of x? Use the convention that positive angles are measured counterclockwise from the +x axis and negative angles are measured clockwise from the +x axis.
Answers
                    Answered by
            Henry
            
    Given: x = -86, y = 75.
tanA = 75/-86 = -0.8721,
A = -41.09 deg.
-41.09 is in 4th quad., but our vectors are in 2nd quad. so we add 180
deg:
-41.09 + 180 = 138.9 deg.
    
tanA = 75/-86 = -0.8721,
A = -41.09 deg.
-41.09 is in 4th quad., but our vectors are in 2nd quad. so we add 180
deg:
-41.09 + 180 = 138.9 deg.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.