Asked by Timmy
A teacher is shot out of a cannon. He leaves the barrel at an angle of 25.0o to the ground with a velocity of 45.0 m/s. How far down range will he land?
Answers
Answered by
bobpursley
time in air:
hf=ho+45*sin25*t-4.9t^2 solve for t.
then
distance= 45*cos25*t
hf=ho+45*sin25*t-4.9t^2 solve for t.
then
distance= 45*cos25*t
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