Asked by Tiffany

Sally has three times as many dimes as nickels and twice as many quarters as dimes.In all she has $5.55. How many coins of each type does she have?
Let 2x=quarters
3x=dimes
x=nickles <---- is that correct please help put
Answered by abby
i think the answer is
3 nickels .15
9 dimes .90
18 quarters 4.50
total 5.50
Answered by Steve
It's easy enough to check.
The numbers add up, and the values add up.

You added wrong at the very end. 4.50 + .90 + .15 does indeed make 5.55

However, your equations do not represent the facts:

x = nickels
3x = dimes
2(3x) = 6x = quarters

5x + 10(3x) + 25(6x) = 555
185x = 555
x=3
Answered by patricia
Megan has three times as many quarters than nickels. She has one less dime than the number of quarters. If she has a total of $4.30, how many of each coin does she have ?
Answered by Trevor
Nickels = x
Quarters = 3x
Dimes = 3x-1

Plug in equation with coin values in ()...
(5)x + (25)3x + (10)3x-1 = 430
5x + 75x + 30x - 10 = 430
80x + 30x - 10 = 430
110x -10 = 430
110x -10 +10 = 430 + 10
110x = 440
x = 4
Nickels = 4 (x)
Quarters = 12 (3x)
Dimes = 11 (3x-1)

4x5=20 N
12x25=300 Q
11x10=110 D /
/
20+300+110= 430 cents \/
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