Asked by kay

Find the volume of 0.120 M hydrochloric acid necessary to react completely with 1.51 g Al(OH)^3

14 years ago

Answered by DrBob222

3HCl + Al(OH)3 ==> 3H2O + AlCl3

moles Al(OH)3 = grams/molar mass
Using the coefficients in the balanced equation, convert moles Al(OH)3 to moles HCl.
Then M HCl = moles HCl/L HCl. You know M and moles HCl, solve for L.

14 years ago

Answered by Anonymous

.1613

12 years ago

Answered by steve

0.4839L

3 years ago

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