7.0 m/(time to fall 5.5 m)
Time to fall Y = = sqrt (2Y/g)
= 1.059 s for Y = 5.5 m
Now use the first equation
A pelican flying along a horizontal path drops a fish from a height of 5.5 m. The fish travels 7.0 m horizontally before it hits the water below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2.
1 answer