what is the length of CE if DC=5x-24, CE= 6x-20, and DE= 55?

Answer 1

I will assume that D , C , and E are points on a straight line, with C between D and E. Then ...
5x-24 + 6x-20= 55
11x= 99
x = 9

then CE = 6(9)-20
= 34