Asked by perfect
Given Q(4;1),T(p;3) and length QT=root of 8 units ,determine the value of p
Answers
Answered by
Reiny
√( (p-4)^2 + (3-1)^2) )= √8
square both sides
(p-4)^2 + 4 = 8
(p-4)^2 = 12
p-4 = ±√12
p = 4 ± 2√3
square both sides
(p-4)^2 + 4 = 8
(p-4)^2 = 12
p-4 = ±√12
p = 4 ± 2√3
Answered by
PerfecT
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Answered by
Anonymous
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