Asked by Tiffany
Kesha dove from Buffalo to Syracuse at an average rate of 48miles per hour. On the return trip along the same road she was able to travel at an average rate of 60 miles per hour.The trip from Buffalo to Syracuse took one- half hour longer than the return trip. How long did the return trip take?
Answers
Answered by
Steve
If d is the distance, then
the time it took at 48mph is d/48
the time it took at 6mph is d/60
d/48 = d/60 + 1/2
d(1/48 - 1/60) = 1/2
d/240 = 1/2
d = 120
time at 48mph = 2.5 hr
time at 60mph = 2 hr
the time it took at 48mph is d/48
the time it took at 6mph is d/60
d/48 = d/60 + 1/2
d(1/48 - 1/60) = 1/2
d/240 = 1/2
d = 120
time at 48mph = 2.5 hr
time at 60mph = 2 hr
Answered by
Reiny
let the distance between Buffalo and Syracuse be d miles
time for trip from B to S = d/48
time for trip from S to B = d/60
d/48 - d/60 = 1/2
times 240 , the LCD
5d - 4d = 120
d = 120 miles between the two cities.
so return trip took 120/60 = 2 hrs
time for trip from B to S = d/48
time for trip from S to B = d/60
d/48 - d/60 = 1/2
times 240 , the LCD
5d - 4d = 120
d = 120 miles between the two cities.
so return trip took 120/60 = 2 hrs
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