Asked by sam
Use the table below to find the products of the two polynomials. Enter your answer in descending order in the box below. Enter exponents using the caret ( ^ ). For example, you would enter as 4x^2. Do not enter spaces in your answer.
(x3 + 2x2 - 2)(x3 - 3x + 3)how do you do this?
(x3 + 2x2 - 2)(x3 - 3x + 3)how do you do this?
Answers
Answered by
Steve
Just multiply term by term, just as you do with a multi-digit number:
124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)
(x^3 + 2x^2 - 2)(x^3 - 3x + 3)
= x^3(x^3 - 3x + 3) + 2x^2(x^3 - 3x + 3) - 2(x^3 - 3x + 3)
= x^6 - 3x^4 + 3x^3 + 2x^5 - 6x^3 + 6x^2 - 2x^3 + 6x - 6
= x^6 + 2x^5 - 3x^4 - 5x^3 + 6x^2 + 12x - 6
124* 327 = 100(300+20+7) + 20(300+20+7) + 4(300+20+7)
(x^3 + 2x^2 - 2)(x^3 - 3x + 3)
= x^3(x^3 - 3x + 3) + 2x^2(x^3 - 3x + 3) - 2(x^3 - 3x + 3)
= x^6 - 3x^4 + 3x^3 + 2x^5 - 6x^3 + 6x^2 - 2x^3 + 6x - 6
= x^6 + 2x^5 - 3x^4 - 5x^3 + 6x^2 + 12x - 6
Answered by
Steve
Ahem. Make that + 6x
Answered by
sam
thanks :)
Answered by
sam
(x7 + x4 + x)(x3 - 1)
can u help me with this one 2
can u help me with this one 2
Answered by
sam
it was wrong the first one
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