Asked by Millie
find the horizontal tangents of the curve and show work
y=5x^3-3x^5
y=5x^3-3x^5
Answers
Answered by
bobpursley
y'=15x^2-15x^4=0 (ie horizontal tangents have slope zero)
0=15x^2(1-x^2)=15x^2(1+x)(1-x)
x=0, x=+-1
find y for each of those
eg, when x=1, y=2, so equation is y=2
0=15x^2(1-x^2)=15x^2(1+x)(1-x)
x=0, x=+-1
find y for each of those
eg, when x=1, y=2, so equation is y=2
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