Asked by Katie A
Divide and siplify
w^8/W^5
would it be 1/w^13 I add the 8and the 5 right???/
w^8/W^5
would it be 1/w^13 I add the 8and the 5 right???/
Answers
Answered by
Steve
Since you are dividing, you subtract exponents.
w^8 = w*w*w*w*w*w*w*w
w^5 = w*w*w*w*w
Write that as a fraction, and 5 of the w's cancel, leaving w^(8-5) = w^3
If that seems weird, just try it with mnubers
2^8 = 256
2^5 = 32
256/32 = 8 = 2^3
w^8 = w*w*w*w*w*w*w*w
w^5 = w*w*w*w*w
Write that as a fraction, and 5 of the w's cancel, leaving w^(8-5) = w^3
If that seems weird, just try it with mnubers
2^8 = 256
2^5 = 32
256/32 = 8 = 2^3
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