Question
Sovle
w^2-13w+42=0
I get -6,-7 is this correct????
w^2-13w+42=0
I get -6,-7 is this correct????
Answers
Robert
yes it is, as:
w^2-13w+42=0
(w-7)(w-6)=0
w^2-13w+42=0
(w-7)(w-6)=0
Anonymous
You correctly factored the trinomial, but that's not the solution.
If (x-6)(x-7) = 0, then the equation is true only if one of the factors is zero.
So, the solution is, x=6 or 7
If (x-6)(x-7) = 0, then the equation is true only if one of the factors is zero.
So, the solution is, x=6 or 7