Asked by Hannah
sovle: (3x - 2y)^2
The answer is 9x^2 + 4y^2 - 12xy but I do not know how to get the 12xy part.
20 - 4/5x is greater that or equal to 16, then:
The answer is x is less thatn or equal to 5 but again I do not know how to get this.
The answer is 9x^2 + 4y^2 - 12xy but I do not know how to get the 12xy part.
20 - 4/5x is greater that or equal to 16, then:
The answer is x is less thatn or equal to 5 but again I do not know how to get this.
Answers
Answered by
Damon
(3x - 2y)^2 = (3x-2y)(3x-2y)
You could use FOIL
(3x)(3x)+(3x)(-2y)+(-2y)(3x)+(-2y)(-2y)
= 9x^2 -12xy +4y^2
or use the distributive property of multipication directly
3x(3x-2y) - 2y(3x-2y)
=9 x^2 -6xy -6xy + 4y^2
= 9x^2 - 12 xy + 4y^2
You could use FOIL
(3x)(3x)+(3x)(-2y)+(-2y)(3x)+(-2y)(-2y)
= 9x^2 -12xy +4y^2
or use the distributive property of multipication directly
3x(3x-2y) - 2y(3x-2y)
=9 x^2 -6xy -6xy + 4y^2
= 9x^2 - 12 xy + 4y^2
Answered by
Damon
20 - 4/5x >/= 16
If that is what you mean then
100 x - 4 >/= 80 x
20 x - 4 >/= 0
20 x >/= 4
x >/= 1/5
or if you mean
20 - (4/5)x >/= 16
20 - 16 >/= (4/5) x
4 >/= (4/5) x
5 >/= x
If that is what you mean then
100 x - 4 >/= 80 x
20 x - 4 >/= 0
20 x >/= 4
x >/= 1/5
or if you mean
20 - (4/5)x >/= 16
20 - 16 >/= (4/5) x
4 >/= (4/5) x
5 >/= x
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