Asked by Lydia
Lee Holmes deposited $16,600 in a new savings account at 9% interest compounded semiannually. At the beginning of year 4, Lee deposits an additional $41,600 at 9% interest compounded semiannually.
At the end of year 6, what is the balance in Lee’s account?
I have tried and I got $44691.78 but that is incorrect. I solved each part separately then added the what he deposited. PLEASE HELP ME!!
Answers
Answered by
Steve
It's not quite clear from the language, but it appears that after 3 years, an additional deposit was made, and then the current balance is left to draw 9% interest for two more years. If that's the case, then
to start: 16600
at the end of year 3, he has 16600*1.045^6 = 21617.52
Add 41600 = 63217.52
After two more years, 63217.52*1.045^4 = 75388.07
to start: 16600
at the end of year 3, he has 16600*1.045^6 = 21617.52
Add 41600 = 63217.52
After two more years, 63217.52*1.045^4 = 75388.07
Answered by
Steve
Oops. That just takes us 5 years.
63217.52*1.045^6 = 82325.66
63217.52*1.045^6 = 82325.66
Answered by
Reiny
Make a time graph to see how the periods work
amount = 16600(1.045)^12 + 41600(1.045)^6
= 82 325.65
amount = 16600(1.045)^12 + 41600(1.045)^6
= 82 325.65
Answered by
Lydia
Thannk you both of you but both answers are incorrect. I can input the answer to see if it is right and both are wrong. We are all missing something. If anyone else wants to try please do!!!
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