Asked by Emily
a 75 kg person escapes from a burning building by jumping from a window 30 m above a catching net. Acceleration due to gravity is 9.81 m/s^2. Assuming air resistance is simply a constant 96 N force on the person during the fall, determine the person's velocity just before hitting the net. answer in m/s.
Answers
Answered by
Neha
so Fg = 75*9.81 = 735.75 N
Fnet = ma
Fair - Fg = ma
96 - 735.75 = 75 * a
a = -8.53 m/s2
Vf2 = Vo2 +2ax
Vf2 = 0 + 2(-8.53)(-30)
Vf2 = 511.8
Vf = -22.63 m/s //neg b/c downward direction
Fnet = ma
Fair - Fg = ma
96 - 735.75 = 75 * a
a = -8.53 m/s2
Vf2 = Vo2 +2ax
Vf2 = 0 + 2(-8.53)(-30)
Vf2 = 511.8
Vf = -22.63 m/s //neg b/c downward direction
Answered by
olive
DO NOT MAKE THE ANSWER NEGATIVE ^^^^^^^ This is velocity NOT speed
Answered by
olive branch
stupid olive
Answered by
olive branch
silly dumb stupid olive
Answered by
olive branch
silly goose olive
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