Asked by Bolu
The foci and vertice of 2x^2+5y^2+8x+10y+3=0
Answers
Answered by
Reiny
let's complete the square
2(x^2 + 4x + ....) + 5(y^2 + 2y + ...) = -3
2(x^2 + 4x + 4) + 5(y^2 + 2y + 1) = -3 + 8 + 5
2(x+2)^2 + 5(y+1)^2 = 10
divide by 10
(x+2)^2/5 + (y+1)^2/2 = 1
can you take it from there?
2(x^2 + 4x + ....) + 5(y^2 + 2y + ...) = -3
2(x^2 + 4x + 4) + 5(y^2 + 2y + 1) = -3 + 8 + 5
2(x+2)^2 + 5(y+1)^2 = 10
divide by 10
(x+2)^2/5 + (y+1)^2/2 = 1
can you take it from there?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.