Question
There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)
how do you find the degrees of P?
how do you find the degrees of P?
Answers
Reiny
since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)
then cosß = .3420
then angle ß = 70º
notice you would get the same if you took
sin ß = .9397
ß = 70º and notice that
.3420^2 + .9397^2 = 1
then cosß = .3420
then angle ß = 70º
notice you would get the same if you took
sin ß = .9397
ß = 70º and notice that
.3420^2 + .9397^2 = 1
s
thanks