Asked by Maci
sodium metal reacts violently with water to produce aqueous sodium hydroxide and hydrogen gas. calculate the enthalpy change for this reaction.
Answers
Answered by
DrBob222
Write the equation and balance it.
Look up Hf for the products and reactants.
Then DHrxn = (n*DHfproducts) - (n*DHfreactants)
Look up Hf for the products and reactants.
Then DHrxn = (n*DHfproducts) - (n*DHfreactants)
Answered by
Maci
is it:
Na + H2O -> ????
Hf is hafnium.
i don't know this stuff.
Na + H2O -> ????
Hf is hafnium.
i don't know this stuff.
Answered by
DrBob222
2Na + H2O ==> H2 + 2NaOH
Hf is H<sub>f</sub> = heat formation and hafnium is not involved with anything your are doing.
Look up the delta H<sub>f</sub> values (they should be listed in your text as delta H<sup>o</sub><sub>f</sub> then
follow the equation I gave you. DHf stands for delta H<sup>o</sup><sub>f</sub>.
Hf is H<sub>f</sub> = heat formation and hafnium is not involved with anything your are doing.
Look up the delta H<sub>f</sub> values (they should be listed in your text as delta H<sup>o</sub><sub>f</sub> then
follow the equation I gave you. DHf stands for delta H<sup>o</sup><sub>f</sub>.
Answered by
DrBob222
I made a typo trying to type the sub subscripts and superscripts.
.....should be listed in your text as delta H<sup>o</sup><sub>f</sub> then follow......
.....should be listed in your text as delta H<sup>o</sup><sub>f</sub> then follow......
Answered by
Maci
i balanced the equation:
2 Na + 2 H2O = H2 + 2 NaOH.
What delta Hf value am i suppose to look up?
2 Na + 2 H2O = H2 + 2 NaOH.
What delta Hf value am i suppose to look up?
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