Asked by Amanda
Sodium metal and water reacts to form hydrogen and sodium hydroxide. If 5.98g of sodium react with water to form .26g of hydrogen and 10.40g of sodium hydroxide, what mass of water was consumed in the reaction?
Answers
Answered by
DrBob222
Write the balanced equation.
2Na + 2H2O ==> 2NOH + H2.
Convert 5.98 g Na to moles. moles - grams/molar mass.
Using the coefficients in the balanced equation, convert moles Na to moles H2O. Now convert mols H2O to grams H2O. g = moles x molar mass.
Note: You may wish to confirm that 5.98 g Na actually produces 0.26 g H2 and 10.40 g NaOH to assure yourself that there are no limiting reagents here. I confirmed that first.
2Na + 2H2O ==> 2NOH + H2.
Convert 5.98 g Na to moles. moles - grams/molar mass.
Using the coefficients in the balanced equation, convert moles Na to moles H2O. Now convert mols H2O to grams H2O. g = moles x molar mass.
Note: You may wish to confirm that 5.98 g Na actually produces 0.26 g H2 and 10.40 g NaOH to assure yourself that there are no limiting reagents here. I confirmed that first.
Answered by
first
4.68
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