Asked by Sejul
radiators sell for $350. Let x be radiators. profit shown by equation
p= -.01x^2 +375x -600,000.
What number of radiators will produce the larget possible profit?
What is the largest possible profit?
p= -.01x^2 +375x -600,000.
What number of radiators will produce the larget possible profit?
What is the largest possible profit?
Answers
Answered by
MathMate
Since the school subject did not mention calculus, I assume this has to be done without using calculus.
Given quadratic function:
p= -.01x^2 +375x -600,000
Complete squares to find vertex:
p=-0.01(x²-37500x)-600000
=-0.01(x-18750)²-600000+18750²*0.01
=-0.01(x-18750)²)+2915625
which shows us that the vertex is at
(18750, 2915625)
profit=$2915625 at x=18750.
Given quadratic function:
p= -.01x^2 +375x -600,000
Complete squares to find vertex:
p=-0.01(x²-37500x)-600000
=-0.01(x-18750)²-600000+18750²*0.01
=-0.01(x-18750)²)+2915625
which shows us that the vertex is at
(18750, 2915625)
profit=$2915625 at x=18750.
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