Question
If 5 times the smaller of two numbers is subtracted from twice the larger the result is 16. If the larger is increased by 3 times the smaller, the result is 63. Find the numbers.
Answers
let
a = smaller
b = larger
2b - 5a = 16
b + 3a = 63
2b - 5a = 16
2b + 6a = 126
11a = 110
a = 10
b = 33
a = smaller
b = larger
2b - 5a = 16
b + 3a = 63
2b - 5a = 16
2b + 6a = 126
11a = 110
a = 10
b = 33
If THREE times the smaller of two numbers is subtracted from twice the larger, the result is -1. If the larger is increased by two times the smaller, the result is 24. Find the numbers.
Let
sm=a*3=3a
lg=b*2=2b
2b-3a=-1-----eqn 1
b+2a=24----eqn2, then
a=7
b=10.
sm=a*3=3a
lg=b*2=2b
2b-3a=-1-----eqn 1
b+2a=24----eqn2, then
a=7
b=10.
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