Question

Assume r and s are the roots of the quadratic equation ax^2 + bx + c = 0, show that r + s = -b/a and rs = c/a.

Answer 1

If r and s are the roots , then
(x-r)(x-s) = 0
x^2 - rx - sx + rs = 0

x^2 +<b> x(-r-s) + rs</b> = 0

compare with
ax^2 + bx + c = 0
or
x^2 + <b>(b/a)x + c/a</b> = 0

then -r-s = b/x ---> r+s = -b/a
and c/a = rs

so r+s = -b/a and rs = c/a