Asked by Thomas
Given that the roots of the equation 3x^2+x+2=0 are a and b, show that 27a^4=11a+10.
Answers
Answered by
Steve
Using brute force, since a = (-1+√23 i)/6
27a^4 = (49+11√23 i)/6
and so does 11a+10
27a^4 = (49+11√23 i)/6
and so does 11a+10
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