Asked by lkra
what is the new boiling point for a solution prepared from 1.40 mol of KCI 1.00kg of water?
Answers
Answered by
DrBob222
molality = moles/kg solvent. Solve for molality.
delta T = i*Kb*m
i = 2 for KCl.
Solve for delta T.
Add delta T to 100 C.
delta T = i*Kb*m
i = 2 for KCl.
Solve for delta T.
Add delta T to 100 C.
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