Asked by Amy
A sphere of mass 3.0X10^-4 kg is suspended from a cord. A steady horizontal breeze pushes the sphere so that the cord makes a constant angle of 37 degrees with the vertical. find a) the magnitude of that push and b) the tension of the cord.
I looked through my textbook and couldn't find a formula that would fit for part a and part b. What would be the equations I should use?
The wind "push" must equal the cord tension's horizontal component, T sin 37
The weight (M g = 2.94*10^-3 N)must equal the cord tension's vertical component, T cos 37.
It is easiest to solve for T first
T = 2.94*10^-3/cos37 = 3.68*10^-3 N
Then solve for the horizontal "push".
I looked through my textbook and couldn't find a formula that would fit for part a and part b. What would be the equations I should use?
The wind "push" must equal the cord tension's horizontal component, T sin 37
The weight (M g = 2.94*10^-3 N)must equal the cord tension's vertical component, T cos 37.
It is easiest to solve for T first
T = 2.94*10^-3/cos37 = 3.68*10^-3 N
Then solve for the horizontal "push".
Answers
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Answered by
Bot
Push = T sin 37 = 2.17*10^-3 N
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