Asked by Monique
For each precipitation reaction, calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant.
2KI(aq) + Pb(NO3)2(aq)--->PbI2(s) + 2KNO3(aq)
Not looking for the answer I really want to know if I did it correctly
17.3g Pb(NO3)/331.22gPb(NO3) x 2 mol KI x 166g KI = 17.3G KI
2KI(aq) + Pb(NO3)2(aq)--->PbI2(s) + 2KNO3(aq)
Not looking for the answer I really want to know if I did it correctly
17.3g Pb(NO3)/331.22gPb(NO3) x 2 mol KI x 166g KI = 17.3G KI
Answers
Answered by
DrBob222
It looks ok to me including the answer.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.