Asked by Fran
If 200. mL of 2.00 M H3PO4 solution is added to 600. mL of 2.00 M NaOH solution, the resulting solution will be ____ molar in Na3PO4.
Answers
Answered by
bobpursley
you have .2*2 moles H2PO4
you have .6*2 moles of NaOH
balanced equation:
H3PO4 + 3NaOH>> Na3PO4 + H2O
so for each mole of acid, you need three times that amount of base.
.4moles acid, need 1.2 moles of base, but you have 1.2, which is magically just right. So, you should get .4 moles of trisodiumphosphate.
Molarity= .4 moles/(.800L+moleswater made)
moleswater made is .4 moles, or 18*.4grams, or 7.2 ml water or
molarity= .4moles/(.8072) then reduce that to three significant digits.
check my work.
you have .6*2 moles of NaOH
balanced equation:
H3PO4 + 3NaOH>> Na3PO4 + H2O
so for each mole of acid, you need three times that amount of base.
.4moles acid, need 1.2 moles of base, but you have 1.2, which is magically just right. So, you should get .4 moles of trisodiumphosphate.
Molarity= .4 moles/(.800L+moleswater made)
moleswater made is .4 moles, or 18*.4grams, or 7.2 ml water or
molarity= .4moles/(.8072) then reduce that to three significant digits.
check my work.
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