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H3PO4+3Ca(OH)2=Ca3(PO4)2=6H2O

If 44.6g of Ca3(PO4)2 are formed in the above reaction, how many moles of H3PO4 must have been consumed?

1 answer

First, balance the equation. It isn't balanced now.
mols Ca3(PO4)2 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols Ca3(PO4)2 to mols H3PO4.
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