Asked by Jimmy
The target is to be dropped from the point
A at t = 0, the same moment as the gun is
fired. The bullet hits the target at a point
P. Let the initial speed of the bullet be v0 =
106 m/s, let the angle between the vector v0
and the horizontal (x) direction be θ = 57.3
and let AB = 91 m. The distance d = OB is
the x-coordinate of the target.
The acceleration of gravity is 9.8 m/s^2
The height BP where the collision takes
place is
A at t = 0, the same moment as the gun is
fired. The bullet hits the target at a point
P. Let the initial speed of the bullet be v0 =
106 m/s, let the angle between the vector v0
and the horizontal (x) direction be θ = 57.3
and let AB = 91 m. The distance d = OB is
the x-coordinate of the target.
The acceleration of gravity is 9.8 m/s^2
The height BP where the collision takes
place is
Answers
Answered by
Jimmy
i know i have to find the x component and y component in this equation
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