The bulls-eye on a target has a diameter of 3 inches. The whole target has a diameter of 15 inches. What part of the whole target is the bulls-eye? Explain.
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4 answers
3/15 = 1/5
area of bulls-eye = π(1.5)^2 = 2.25π
area of whole target = π(7.5)^2 = 56.25π
so the bull's-eye is
2.25π/56.25π = 1/25
which reflects the property that the areas of different circles are proportional to the square of their corresponding diameters
ratio of diameters = 3 : 15 = 1 : 5
so ratio of areas = 1^2 : 5^2 = 1 : 25
area of whole target = π(7.5)^2 = 56.25π
so the bull's-eye is
2.25π/56.25π = 1/25
which reflects the property that the areas of different circles are proportional to the square of their corresponding diameters
ratio of diameters = 3 : 15 = 1 : 5
so ratio of areas = 1^2 : 5^2 = 1 : 25
What percent would that be?
The percent would be 0.04%, or 4% because 1/25, in percent form, is 4%.
2 answers