Question
A stone is thrown from ground level at 70m/s. Its speed when it reaches its highest point is 48 m/s. Find the angle, above the horizontal, of the stone’s initial velocity.
Answers
Steve
Check me on this, I'm a little rusty.
The initial velocity is 70. Since the horizontal speed never changed, that means that the x-component was 48. So, cos θ = 48/70, so θ = 46.7°
The initial velocity is 70. Since the horizontal speed never changed, that means that the x-component was 48. So, cos θ = 48/70, so θ = 46.7°
Jimmy
thank you