Asked by Jordan
A stone is thrown from ground level at 72 m/s. Its speed when it reaches its highest point is 46 m/s.
Find the angle, above the horizontal, of the stone's initial velocity.
Answer in units of degree
Find the angle, above the horizontal, of the stone's initial velocity.
Answer in units of degree
Answers
Answered by
Henry
Vo = 72m/s[Ao].
Xo = 46 m/s.
Xo = 72*Cos A = 46.
Cos A = 46/72 = 0.63889.
A = 50.3o
Xo = 46 m/s.
Xo = 72*Cos A = 46.
Cos A = 46/72 = 0.63889.
A = 50.3o
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