Asked by John
Find f(infinity) for the complex function:
f(z) = (iz-5)/(8z+3i)
Thanks,
John
f(z) = (iz-5)/(8z+3i)
Thanks,
John
Answers
Answered by
Steve
Hmmm. I'd do this by making the denomonator real:
(-5+zi)/(8z+3i) * (8z-3i)/(8z-3i)
= (-5+zi)(8z-3i)/(64z^2+9)
= [(-40z + 3z) + (8z^2-15)i]/(64z^2+9)
= -37z/(64z^2+9) + (8z^2-15)/(64z^2+9) i
Now, as z gets huge, all the small constants vanish, and we get
-37/64z + 1/8 i = 1/8 i
(-5+zi)/(8z+3i) * (8z-3i)/(8z-3i)
= (-5+zi)(8z-3i)/(64z^2+9)
= [(-40z + 3z) + (8z^2-15)i]/(64z^2+9)
= -37z/(64z^2+9) + (8z^2-15)/(64z^2+9) i
Now, as z gets huge, all the small constants vanish, and we get
-37/64z + 1/8 i = 1/8 i
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.