6. If 4.0 × 1018 J of work done on a point charge changes its electric potential difference by 25.0 V, then what is the magnitude of the charge?

(Points : 1)
1.6 × 101^9 C

4.0 × 101^9 C

1.6 × 101^8 C

4.0 × 101^8 C

7. Two parallel plates have an electric field strength between them of 1.0 × 103 N/C and an electric potential difference of 50.0 V. How far apart are the plates?
(Points : 1)
1.0 cm

2.0 cm

5.0 cm

10.0 cm

1 answer

Voltage * charge = work done by E field on charge

Same thing really
Volts = E * d

Use METERS volts, Coulombs