5x^2-10x+d=0

Determine an integer value for d such that the equation has rational, non zero roots

Please show me the steps and how to answer this question :) thanks:)

3 answers

depends on the value of the discriminant D
where D = b^2 - 4ac
remember that if
D > 0 we have 2 distinct real roots
D = 0 we have 1 real root
D <0 we have no real roots

So take all 3 cases , I will do one them, you do the rest.

D > 0
10^2 - 4(5)d > 0
-20d > -100
d < 5
one such value of d is -20

Wolfram shows 2 real roots
http://www.wolframalpha.com/input/?i=plot+y+%3D5x%5E2-10x+-+20
Oh ok , I was doing this exact thing and my answer was the same as yours but then when I checked my answers in my text book it gave me -20, that's why I was confused . Thank you so much:) really appreciate it:)
how do you divide